| 如何使用asp上传HTML5 单input多文件 |
aXfBHl http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
8srpqo http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
4XT5ic http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
1ZR1FK http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
qnx5Xa http://blog.numino.net/
End if
k9aP4e http://blog.numino.net/
Next
hf0YKM http://blog.numino.net/
It might be worth trying the same approach - ie:
EvedLE http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
PgeHnb http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
l5JAuB http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
nGb1oQ http://blog.numino.net/
End if
HCi6Ok http://blog.numino.net/
Next
uqdy4x http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
U9r7Ay http://blog.numino.net/
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