| 如何使用asp上传HTML5 单input多文件 |
w0r3uE http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
rOqRPq http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
43W5Om http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
87Tib3 http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
5K8HsU http://blog.numino.net/
End if
4oqH7K http://blog.numino.net/
Next
cJc9km http://blog.numino.net/
It might be worth trying the same approach - ie:
JMr3Em http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
Y8lTb4 http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
6jA309 http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
S3iB93 http://blog.numino.net/
End if
z0tsuJ http://blog.numino.net/
Next
e3i1cW http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
kAGytA http://blog.numino.net/
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