| 如何使用asp上传HTML5 单input多文件 |
A2Z8Gx http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
62FM4p http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
652Kor http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
MiiVi1 http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
2E8O4x http://blog.numino.net/
End if
S66pte http://blog.numino.net/
Next
MKUYos http://blog.numino.net/
It might be worth trying the same approach - ie:
GbEG7V http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
4Rg0oF http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
2z60Y5 http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
F92Y6e http://blog.numino.net/
End if
rFrLNM http://blog.numino.net/
Next
Sk3Pku http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
avSJ4B http://blog.numino.net/
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