| 如何使用asp上传HTML5 单input多文件 |
I3In4w http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
en5M9F http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
5mSkG4 http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
psgzOB http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
9ZT5Y5 http://blog.numino.net/
End if
t9pf9s http://blog.numino.net/
Next
LxdNL5 http://blog.numino.net/
It might be worth trying the same approach - ie:
g4DG5g http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
n7Yqha http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
4O5aEy http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
wsdV5A http://blog.numino.net/
End if
2FZ3Z3 http://blog.numino.net/
Next
irJtmx http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
HAZ0bK http://blog.numino.net/
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