| 如何使用asp上传HTML5 单input多文件 |
NWj7qa http://blog.numino.net/
If you have a form which submits multiple values of the same form variable you can separate them as follows.
0qu2C1 http://blog.numino.net/
For i = 1 to Request.form("myforminput").Count
090Y3N http://blog.numino.net/
If Request.form("myforminput")(i) <> "" then
Ve1Vog http://blog.numino.net/
Response.write Request.form("myforminput")(i) & "<br />"
HR2xBB http://blog.numino.net/
End if
mXTxQP http://blog.numino.net/
Next
rPW08g http://blog.numino.net/
It might be worth trying the same approach - ie:
eJwt8C http://blog.numino.net/
For i = 1 to (objUpload.Form("thefile").value).Count
KwN0I0 http://blog.numino.net/
If (objUpload.Form("thefile").value)(i) <> "" then
qel28P http://blog.numino.net/
Response.write (objUpload.Form("thefile").value)(i) & "<br />"
5oj3HE http://blog.numino.net/
End if
xbcpFJ http://blog.numino.net/
Next
Z4txwu http://blog.numino.net/
Because there's a third party component involved it may complicate things so I can't guarantee this will work. Check the component's documentation if it is available, particularly with respect to counting the number of files uploaded.
1cNc5s http://blog.numino.net/
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